9HP is the trademark name for the ZF Friedrichshafen 9-speed automatic transmission models (9 -speed transmission with H ydraulic converter and P lanetary gearsets) for transverse engine applications, designed by ZF's subsidiary in Saarbrücken and built in Gray Court, South Carolina .[ 1] It is used in front-wheel drive and all-wheel drive vehicles.
The 9HP is the world's first 9-speed automatic transmission for passenger cars. Land Rover and Jeep launched it at the 2013 Geneva Motor Show .[ 2] The 2014 Jeep Cherokee then was the first car with this transmission delivered to customers.
Key Data
Gear Ratios[ a]
Model
First Deliv- ery
Gear
Total Span
Avg. Step
Components
Nomenclature
R
1
2
3
4
5
6
7
8
9
Nomi- nal
Effec- tive
Cen- ter
Total
per Gear[ b]
Gears Count
Cou- pling
Gear- sets
Maximum Input Torque
9HP 28 9HP 48
2013
−3.805
4.700
2.842
1.909
1.382
1.000
0.808
0.699
0.580
0.479
9.808
7.940
1.501
1.330
4 Gearsets 3 Brakes 3 Clutches
1.111
9[ b]
H[ c]
P[ d]
280 N⋅m (207 lb⋅ft )[ e] 450 N⋅m (332 lb⋅ft )[ f] 480 N⋅m (354 lb⋅ft )[ g]
^ Differences in gear ratios have a measurable, direct impact on vehicle dynamics, performance, waste emissions as well as fuel mileage
^ a b Forward gears only
^ Hydraulic torque converter · German : H ydraulischer Wandler oder Drehmomentwandler
^ Planetary gearing · German : P lanetenradsätze
^ for both gasoline and diesel[ 1]
^ for gasoline[ 1]
^ for diesel[ 1]
Specifications
Combined Parallel and Serial Coupled Gearset Concept For More Gears And Improved Cost-Effectiveness
Gearset Concept: Cost-Effectiveness[ a]
With Assessment
Output: Gear Ratios
InnovationElasticity [ b] Δ Output : Δ Input
Input: Main Components
Total
Gearsets
Brakes
Clutches
9HP Ref. Object
n
O
1
{\displaystyle n_{O1}}
n
O
2
{\displaystyle n_{O2}}
Topic[ b]
n
I
=
n
G
+
{\displaystyle n_{I}=n_{G}+}
n
B
+
n
C
{\displaystyle n_{B}+n_{C}}
n
G
1
{\displaystyle n_{G1}}
n
G
2
{\displaystyle n_{G2}}
n
B
1
{\displaystyle n_{B1}}
n
B
2
{\displaystyle n_{B2}}
n
C
1
{\displaystyle n_{C1}}
n
C
2
{\displaystyle n_{C2}}
Δ Number
n
O
1
−
n
O
2
{\displaystyle n_{O1}-n_{O2}}
n
I
1
−
n
I
2
{\displaystyle n_{I1}-n_{I2}}
n
G
1
−
n
G
2
{\displaystyle n_{G1}-n_{G2}}
n
B
1
−
n
B
2
{\displaystyle n_{B1}-n_{B2}}
n
C
1
−
n
C
2
{\displaystyle n_{C1}-n_{C2}}
Relative Δ
Δ Output
n
O
1
−
n
O
2
n
O
2
{\displaystyle {\tfrac {n_{O1}-n_{O2}}{n_{O2}}}}
n
O
1
−
n
O
2
n
O
2
:
n
I
1
−
n
I
2
n
I
2
{\displaystyle {\tfrac {n_{O1}-n_{O2}}{n_{O2}}}:{\tfrac {n_{I1}-n_{I2}}{n_{I2}}}}
=
n
O
1
−
n
O
2
n
O
2
⋅
n
I
2
n
I
1
−
n
I
2
{\displaystyle ={\tfrac {n_{O1}-n_{O2}}{n_{O2}}}\cdot {\tfrac {n_{I2}}{n_{I1}-n_{I2}}}}
Δ Input
n
I
1
−
n
I
2
n
I
2
{\displaystyle {\tfrac {n_{I1}-n_{I2}}{n_{I2}}}}
n
G
1
−
n
G
2
n
G
2
{\displaystyle {\tfrac {n_{G1}-n_{G2}}{n_{G2}}}}
n
B
1
−
n
B
2
n
B
2
{\displaystyle {\tfrac {n_{B1}-n_{B2}}{n_{B2}}}}
n
C
1
−
n
C
2
n
C
2
{\displaystyle {\tfrac {n_{C1}-n_{C2}}{n_{C2}}}}
9HP4HP [ c]
9[ d] 4[ d]
Progress[ b]
10 7
4 2[ e]
3 2
3 3
Δ Number
5
3
2
1
0
Relative Δ
1.250
5
4
{\displaystyle {\tfrac {5}{4}}}
2.917 [ b]
5
4
:
3
7
=
5
4
⋅
7
3
=
35
12
{\displaystyle {\tfrac {5}{4}}:{\tfrac {3}{7}}={\tfrac {5}{4}}\cdot {\tfrac {7}{3}}={\tfrac {35}{12}}}
0.429
3
7
{\displaystyle {\tfrac {3}{7}}}
1.000
2
2
{\displaystyle {\tfrac {2}{2}}}
0.500
1
2
{\displaystyle {\tfrac {1}{2}}}
0.000
0
3
{\displaystyle {\tfrac {0}{3}}}
9HPAisin [ f]
9[ d] 4[ d]
Progress[ b]
10 8
4 3[ g]
3 2
3 3
Δ Number
3
2
1
1
0
Relative Δ
0.500
3
6
{\displaystyle {\tfrac {3}{6}}}
2.000 [ b]
3
6
:
2
8
=
1
2
⋅
4
1
=
2
1
{\displaystyle {\tfrac {3}{6}}:{\tfrac {2}{8}}={\tfrac {1}{2}}\cdot {\tfrac {4}{1}}={\tfrac {2}{1}}}
0.250
2
8
{\displaystyle {\tfrac {2}{8}}}
0.333
1
3
{\displaystyle {\tfrac {1}{3}}}
0.333
−
1
3
{\displaystyle {\tfrac {-1}{3}}}
0.000
0
3
{\displaystyle {\tfrac {0}{3}}}
9HP8HP [ h]
9[ d] 8[ d]
Current Market Position[ b]
10 9
4 4
3 2
3 3
Δ Number
1
1
0
1
0
Relative Δ
0.125
1
8
{\displaystyle {\tfrac {1}{8}}}
1.125[ b]
1
8
:
1
9
=
1
8
⋅
9
1
=
9
8
{\displaystyle {\tfrac {1}{8}}:{\tfrac {1}{9}}={\tfrac {1}{8}}\cdot {\tfrac {9}{1}}={\tfrac {9}{8}}}
0.111
1
9
{\displaystyle {\tfrac {1}{9}}}
0.000
0
4
{\displaystyle {\tfrac {0}{4}}}
0.500
1
2
{\displaystyle {\tfrac {1}{2}}}
0.000
0
3
{\displaystyle {\tfrac {0}{3}}}
W9A 3-Speed[ i]
9[ d] 3[ d]
Historical Market Position[ b]
10 7
4 2
3 3
3 2
Δ Number
6
3
2
0
1
Relative Δ
2.000
6
3
{\displaystyle {\tfrac {6}{3}}}
4.667 [ b]
6
3
:
3
7
=
2
1
⋅
7
3
=
14
3
{\displaystyle {\tfrac {6}{3}}:{\tfrac {3}{7}}={\tfrac {2}{1}}\cdot {\tfrac {7}{3}}={\tfrac {14}{3}}}
0.429
3
7
{\displaystyle {\tfrac {3}{7}}}
1.000
1
1
{\displaystyle {\tfrac {1}{1}}}
0.000
0
3
{\displaystyle {\tfrac {0}{3}}}
0.500
1
2
{\displaystyle {\tfrac {1}{2}}}
^ Progress increases cost-effectiveness and is reflected in the ratio of forward gears to main components. It depends on the power flow:
parallel: using the two degrees of freedom of planetary gearsets
to increase the number of gears
with unchanged number of components
serial: in-line combined planetary gearsets without using the two degrees of freedom
to increase the number of gears
a corresponding increase in the number of components is unavoidable
^ a b c d e f g h i j Innovation Elasticity Classifies Progress And Market Position
Automobile manufacturers drive forward technical developments primarily in order to remain competitive or to achieve or defend technological leadership. This technical progress has therefore always been subject to economic constraints
Only innovations whose relative additional benefit is greater than the relative additional resource input, i.e. whose economic elasticity is greater than 1, are considered for realization
The required innovation elasticity of an automobile manufacturer depends on its expected return on investment. The basic assumption that the relative additional benefit must be at least twice as high as the relative additional resource input helps with orientation
negative, if the output increases and the input decreases, is perfect
2 or above is good
1 or above is acceptable (red)
below this is unsatisfactory (bold)
^ Direct Predecessor
To reflect the progress of the specific model change
^ a b c d e f g h plus 1 reverse gear
^ combined as a compound Ravigneaux gearset
^ Market Predecessor
^ of which two gearstets are combined as a compound Ravigneaux gearset
^ Current Reference Standard (Benchmark)
The 8HP has become the new reference standard (benchmark) for automatic transmissions. Although designed for longitudinal installation, it is nevertheless the industry standard.
^ Historical Reference Standard (Benchmark)
3-speed transmissions with torque converters have established the modern market for automatic transmissions and thus made it possible in the first place, as this design proved to be a particularly successful compromise between cost and performance
It became the archetype and dominated the world market for around 3 decades, setting the standard for automatic transmissions. It was only when fuel consumption became the focus of interest that this design reached its limits, which is why it has now completely disappeared from the market
What has remained is the orientation that it offers as a reference standard (point of reference, benchmark) for this market for determining progressiveness and thus the market position of all other, later designs
All transmission variants consist of 7 main components
Typical examples are
Gearset Concept: Quality
The 9HP is only 0.24 inches (6 mm) longer than, and weighs 16.5 lbs (7.5 kg) less than, the outgoing six-speed transmission. The compact packaging is achieved by using a number of innovative design features: a new compact hydraulic vane-type pump, two patented dog clutches ,[ 3] which replace bulkier conventional clutch packs, and a nested gear set.[ 2] ZF claims that it is able to save an average of 16% in fuel compared with current 6-speed automatic transmissions.[ 1]
Gear Ratio Analysis[ a]
In-Depth Analysis[ b] With Assessment And Torque Ratio[ c] And Efficiency Calculation[ d]
Planetary Gearset: Teeth[ e]
Count
Nomi- nal[ f] Effec- tive[ g]
Cen- ter[ h]
Avg.[ i]
Model Type
Version First Delivery · Weight
S4 [ j] R4 [ k]
S3 [ l] R3 [ m]
S2 [ n] R2 [ o]
S1 [ p] R1 [ q]
Brakes Clutches
Ratio Span
Gear Step[ r]
Gear
R
1
2
3
4
5
6
7
8
9
Gear Ratio[ b]
i
R
{\displaystyle {i_{R}}}
[ b]
i
1
{\displaystyle {i_{1}}}
[ b]
i
2
{\displaystyle {i_{2}}}
[ b]
i
3
{\displaystyle {i_{3}}}
[ b]
i
4
{\displaystyle {i_{4}}}
[ b]
i
5
{\displaystyle {i_{5}}}
[ b]
i
6
{\displaystyle {i_{6}}}
[ b]
i
7
{\displaystyle {i_{7}}}
[ b]
i
8
{\displaystyle {i_{8}}}
[ b]
i
9
{\displaystyle {i_{9}}}
[ b]
Step[ r]
−
i
R
i
1
{\displaystyle -{\frac {i_{R}}{i_{1}}}}
[ s]
i
1
i
1
{\displaystyle {\frac {i_{1}}{i_{1}}}}
i
1
i
2
{\displaystyle {\frac {i_{1}}{i_{2}}}}
[ t]
i
2
i
3
{\displaystyle {\frac {i_{2}}{i_{3}}}}
i
3
i
4
{\displaystyle {\frac {i_{3}}{i_{4}}}}
i
4
i
5
{\displaystyle {\frac {i_{4}}{i_{5}}}}
i
5
i
6
{\displaystyle {\frac {i_{5}}{i_{6}}}}
i
6
i
7
{\displaystyle {\frac {i_{6}}{i_{7}}}}
i
7
i
8
{\displaystyle {\frac {i_{7}}{i_{8}}}}
i
8
i
9
{\displaystyle {\frac {i_{8}}{i_{9}}}}
Δ Step[ u] [ v]
i
1
i
2
:
i
2
i
3
{\displaystyle {\tfrac {i_{1}}{i_{2}}}:{\tfrac {i_{2}}{i_{3}}}}
i
2
i
3
:
i
3
i
4
{\displaystyle {\tfrac {i_{2}}{i_{3}}}:{\tfrac {i_{3}}{i_{4}}}}
i
3
i
4
:
i
4
i
5
{\displaystyle {\tfrac {i_{3}}{i_{4}}}:{\tfrac {i_{4}}{i_{5}}}}
i
4
i
5
:
i
5
i
6
{\displaystyle {\tfrac {i_{4}}{i_{5}}}:{\tfrac {i_{5}}{i_{6}}}}
i
5
i
6
:
i
6
i
7
{\displaystyle {\tfrac {i_{5}}{i_{6}}}:{\tfrac {i_{6}}{i_{7}}}}
i
6
i
7
:
i
7
i
8
{\displaystyle {\tfrac {i_{6}}{i_{7}}}:{\tfrac {i_{7}}{i_{8}}}}
i
7
i
8
:
i
8
i
9
{\displaystyle {\tfrac {i_{7}}{i_{8}}}:{\tfrac {i_{8}}{i_{9}}}}
Shaft Speed
i
1
i
R
{\displaystyle {\frac {i_{1}}{i_{R}}}}
i
1
i
1
{\displaystyle {\frac {i_{1}}{i_{1}}}}
i
1
i
2
{\displaystyle {\frac {i_{1}}{i_{2}}}}
i
1
i
3
{\displaystyle {\frac {i_{1}}{i_{3}}}}
i
1
i
4
{\displaystyle {\frac {i_{1}}{i_{4}}}}
i
1
i
5
{\displaystyle {\frac {i_{1}}{i_{5}}}}
i
1
i
6
{\displaystyle {\frac {i_{1}}{i_{6}}}}
i
1
i
7
{\displaystyle {\frac {i_{1}}{i_{7}}}}
i
1
i
8
{\displaystyle {\frac {i_{1}}{i_{8}}}}
i
1
i
9
{\displaystyle {\frac {i_{1}}{i_{9}}}}
Δ Shaft Speed[ w]
0
−
i
1
i
R
{\displaystyle 0-{\tfrac {i_{1}}{i_{R}}}}
i
1
i
1
−
0
{\displaystyle {\tfrac {i_{1}}{i_{1}}}-0}
i
1
i
2
−
i
1
i
1
{\displaystyle {\tfrac {i_{1}}{i_{2}}}-{\tfrac {i_{1}}{i_{1}}}}
i
1
i
3
−
i
1
i
2
{\displaystyle {\tfrac {i_{1}}{i_{3}}}-{\tfrac {i_{1}}{i_{2}}}}
i
1
i
4
−
i
1
i
3
{\displaystyle {\tfrac {i_{1}}{i_{4}}}-{\tfrac {i_{1}}{i_{3}}}}
i
1
i
5
−
i
1
i
4
{\displaystyle {\tfrac {i_{1}}{i_{5}}}-{\tfrac {i_{1}}{i_{4}}}}
i
1
i
6
−
i
1
i
5
{\displaystyle {\tfrac {i_{1}}{i_{6}}}-{\tfrac {i_{1}}{i_{5}}}}
i
1
i
7
−
i
1
i
6
{\displaystyle {\tfrac {i_{1}}{i_{7}}}-{\tfrac {i_{1}}{i_{6}}}}
i
1
i
8
−
i
1
i
7
{\displaystyle {\tfrac {i_{1}}{i_{8}}}-{\tfrac {i_{1}}{i_{7}}}}
i
1
i
9
−
i
1
i
8
{\displaystyle {\tfrac {i_{1}}{i_{9}}}-{\tfrac {i_{1}}{i_{8}}}}
Torque Ratio[ c]
μ
R
{\displaystyle \mu _{R}}
[ c]
μ
1
{\displaystyle \mu _{1}}
[ c]
μ
2
{\displaystyle \mu _{2}}
[ c]
μ
3
{\displaystyle \mu _{3}}
[ c]
μ
4
{\displaystyle \mu _{4}}
[ c]
μ
5
{\displaystyle \mu _{5}}
[ c]
μ
6
{\displaystyle \mu _{6}}
[ c]
μ
7
{\displaystyle \mu _{7}}
[ c]
μ
8
{\displaystyle \mu _{8}}
[ c]
μ
9
{\displaystyle \mu _{9}}
[ c]
Efficiency
η
n
{\displaystyle \eta _{n}}
[ d]
μ
R
i
R
{\displaystyle {\frac {\mu _{R}}{i_{R}}}}
[ d]
μ
1
i
1
{\displaystyle {\frac {\mu _{1}}{i_{1}}}}
[ d]
μ
2
i
2
{\displaystyle {\frac {\mu _{2}}{i_{2}}}}
[ d]
μ
3
i
3
{\displaystyle {\frac {\mu _{3}}{i_{3}}}}
[ d]
μ
4
i
4
{\displaystyle {\frac {\mu _{4}}{i_{4}}}}
[ d]
μ
5
i
5
{\displaystyle {\frac {\mu _{5}}{i_{5}}}}
[ d]
μ
6
i
6
{\displaystyle {\frac {\mu _{6}}{i_{6}}}}
[ d]
μ
7
i
7
{\displaystyle {\frac {\mu _{7}}{i_{7}}}}
[ d]
μ
8
i
8
{\displaystyle {\frac {\mu _{8}}{i_{8}}}}
[ d]
μ
9
i
9
{\displaystyle {\frac {\mu _{9}}{i_{9}}}}
[ d]
9HP 28 9HP 48
280 Nm[ x] · 2013 · 78 kg (172 lb ) 450 Nm[ y] · 2013 · 86 kg (190 lb ) 480 Nm[ z] · 2013 · 86 kg (190 lb )
42 110
42 110
91[ aa] 133
42 86
3[ ab] 3[ ac]
9.80857.9402[ g] [ s]
1.5007
1.3303[ r]
Gear
R
1
2
3
4
5
6
7
8
9
Gear Ratio[ b]
−3.8049[ s] [ g]
−
3
,
142
,
144
825
,
825
{\displaystyle -{\tfrac {3,142,144}{825,825}}}
4.7001
184
,
832
39
,
325
{\displaystyle {\tfrac {184,832}{39,325}}}
2.8419
369
,
664
130
,
075
{\displaystyle {\tfrac {369,664}{130,075}}}
1.9094
5
,
776
3
,
025
{\displaystyle {\tfrac {5,776}{3,025}}}
1.3818[ v]
76
55
{\displaystyle {\tfrac {76}{55}}}
1.0000
1
1
{\displaystyle {\tfrac {1}{1}}}
0.8081[ w]
34
,
048
42
,
133
{\displaystyle {\tfrac {34,048}{42,133}}}
0.6995 [ v] [ w]
6
,
272
8
,
967
{\displaystyle {\tfrac {6,272}{8,967}}}
0.5802 [ v]
76
131
{\displaystyle {\tfrac {76}{131}}}
0.4792
2
,
176
4
,
541
{\displaystyle {\tfrac {2,176}{4,541}}}
Step
0.8095[ s]
1.0000
1.6538
1.4884
1.3818
1.3818
1.2375
1.1553
1.2056
1.2107
Δ Step[ u]
1.1112
1.0771
1.0000 [ v]
1.1167
1.0711
0.9583 [ v]
0.9958 [ v]
Speed
-1.2353
1.0000
1.6538
2.4615
3.4014
4.7001
5.5816
6.7197
8.1015
9.8085
Δ Speed
1.2353
1.0000
0.6538
0.8077
0.9399
1.2987
1.1161 [ w]
0.9035 [ w]
1.3818
1.7066
Torque Ratio[ c]
-3.5391 –3.4099
4.5931 4.5402
2.7922 2.7675
1.8884 1.8779
1.3742 1.3704
1.0000
0.8005 0.7966
0.6904 0.6857
0.5717 0.5673
0.4653 0.4582
Efficiency
η
n
{\displaystyle \eta _{n}}
[ d]
0.9302 0.8962
0.9772 0.9660
0.9825 0.9738
0.9890 0.9835
0.9945 0.9917
1.0000
0.9906 0.9857
0.9870 0.9803
0.9854 0.9779
0.9710 0.9561
Actuated Shift Elements[ ad]
Brake A[ ae]
❶
❶
❶
❶
❶
Brake C[ af]
❶
❶
❶
Brake D[ ag]
❶
❶
❶
❶
❶
Clutch B[ ah]
❶
❶
❶
❶
Clutch E[ ai]
❶
❶
❶
❶
❶
❶
Clutch F[ aj]
❶
❶
❶
❶
❶
❶
❶
Geometric Ratios: Speed Conversion
Gear Ratio[ b] R & 1 Ordinary[ ak] Elementary Noted[ al]
i
R
=
(
S
1
S
2
−
R
1
R
2
)
(
S
3
+
R
3
)
(
S
4
+
R
4
)
S
1
S
2
R
3
R
4
{\displaystyle i_{R}={\frac {(S_{1}S_{2}-R_{1}R_{2})(S_{3}+R_{3})(S_{4}+R_{4})}{S_{1}S_{2}R_{3}R_{4}}}}
i
1
=
(
S
2
+
R
2
)
(
S
3
+
R
3
)
(
S
4
+
R
4
)
S
2
R
3
R
4
{\displaystyle i_{1}={\frac {(S_{2}+R_{2})(S_{3}+R_{3})(S_{4}+R_{4})}{S_{2}R_{3}R_{4}}}}
i
R
=
(
1
−
R
1
R
2
S
1
S
2
)
(
1
+
S
3
R
3
)
(
1
+
S
4
R
4
)
{\displaystyle i_{R}=\left(1-{\tfrac {R_{1}R_{2}}{S_{1}S_{2}}}\right)\left(1+{\tfrac {S_{3}}{R_{3}}}\right)\left(1+{\tfrac {S_{4}}{R_{4}}}\right)}
i
1
=
(
1
+
R
2
S
2
)
(
1
+
S
3
R
3
)
(
1
+
S
4
R
4
)
{\displaystyle i_{1}=\left(1+{\tfrac {R_{2}}{S_{2}}}\right)\left(1+{\tfrac {S_{3}}{R_{3}}}\right)\left(1+{\tfrac {S_{4}}{R_{4}}}\right)}
Gear Ratio[ b] 2 & 3 Ordinary[ ak] Elementary Noted[ al]
i
2
=
(
S
1
+
R
1
)
(
S
3
+
R
3
)
(
S
4
+
R
4
)
R
1
R
3
R
4
{\displaystyle i_{2}={\frac {(S_{1}+R_{1})(S_{3}+R_{3})(S_{4}+R_{4})}{R_{1}R_{3}R_{4}}}}
i
3
=
(
S
3
+
R
3
)
(
S
4
+
R
4
)
R
3
R
4
{\displaystyle i_{3}={\frac {(S_{3}+R_{3})(S_{4}+R_{4})}{R_{3}R_{4}}}}
i
2
=
(
1
+
S
1
R
1
)
(
1
+
S
3
R
3
)
(
1
+
S
4
R
4
)
{\displaystyle i_{2}=\left(1+{\tfrac {S_{1}}{R_{1}}}\right)\left(1+{\tfrac {S_{3}}{R_{3}}}\right)\left(1+{\tfrac {S_{4}}{R_{4}}}\right)}
i
3
=
(
1
+
S
3
R
3
)
(
1
+
S
4
R
4
)
{\displaystyle i_{3}=\left(1+{\tfrac {S_{3}}{R_{3}}}\right)\left(1+{\tfrac {S_{4}}{R_{4}}}\right)}
Gear Ratio[ b] 5–7 Ordinary[ ak] Elementary Noted[ al]
i
5
=
1
1
{\displaystyle i_{5}={\frac {1}{1}}}
i
6
=
S
3
(
S
1
+
R
1
)
(
S
4
+
R
4
)
S
3
(
S
1
+
R
1
)
(
S
4
+
R
4
)
+
S
1
R
3
S
4
{\displaystyle i_{6}={\frac {S_{3}(S_{1}+R_{1})(S_{4}+R_{4})}{S_{3}(S_{1}+R_{1})(S_{4}+R_{4})+S_{1}R_{3}S_{4}}}}
i
7
=
S
3
(
S
2
+
R
2
)
(
S
4
+
R
4
)
S
3
(
S
2
+
R
2
)
(
S
4
+
R
4
)
+
R
2
R
3
S
4
{\displaystyle i_{7}={\frac {S_{3}(S_{2}+R_{2})(S_{4}+R_{4})}{S_{3}(S_{2}+R_{2})(S_{4}+R_{4})+R_{2}R_{3}S_{4}}}}
i
6
=
1
1
+
R
3
S
3
(
1
+
R
1
S
1
)
(
1
+
R
4
S
4
)
{\displaystyle i_{6}={\tfrac {1}{1+{\tfrac {\tfrac {R_{3}}{S_{3}}}{\left(1+{\tfrac {R_{1}}{S_{1}}}\right)\left(1+{\tfrac {R_{4}}{S_{4}}}\right)}}}}}
i
7
=
1
1
+
R
3
S
3
(
1
+
S
2
R
2
)
(
1
+
R
4
S
4
)
{\displaystyle i_{7}={\tfrac {1}{1+{\tfrac {\tfrac {R_{3}}{S_{3}}}{\left(1+{\tfrac {S_{2}}{R_{2}}}\right)\left(1+{\tfrac {R_{4}}{S_{4}}}\right)}}}}}
Gear Ratio[ b] 4 & 8 & 9 Ordinary[ ak] Elementary Noted[ al]
i
4
=
S
4
+
R
4
R
4
{\displaystyle i_{4}={\frac {S_{4}+R_{4}}{R_{4}}}}
i
8
=
S
3
(
S
4
+
R
4
)
S
4
(
S
3
+
R
3
)
+
S
3
R
4
{\displaystyle i_{8}={\frac {S_{3}(S_{4}+R_{4})}{S_{4}(S_{3}+R_{3})+S_{3}R_{4}}}}
i
9
=
S
3
(
R
1
R
2
−
S
1
S
2
)
(
S
4
+
R
4
)
S
3
(
R
1
R
2
−
S
1
S
2
)
(
S
4
+
R
4
)
+
R
1
R
2
R
3
S
4
{\displaystyle i_{9}={\frac {S_{3}(R_{1}R_{2}-S_{1}S_{2})(S4+R_{4})}{S_{3}(R_{1}R_{2}-S_{1}S_{2})(S_{4}+R_{4})+R_{1}R_{2}R_{3}S_{4}}}}
i
4
=
1
+
S
4
R
4
{\displaystyle i_{4}=1+{\tfrac {S_{4}}{R_{4}}}}
i
8
=
1
1
+
R
3
S
3
1
+
R
4
S
4
{\displaystyle i_{8}={\tfrac {1}{1+{\tfrac {\tfrac {R_{3}}{S_{3}}}{1+{\tfrac {R_{4}}{S_{4}}}}}}}}
i
9
=
1
1
+
R
3
S
3
(
1
−
S
1
S
2
R
1
R
2
)
(
1
+
R
4
S
4
)
{\displaystyle i_{9}={\tfrac {1}{1+{\tfrac {\tfrac {R_{3}}{S_{3}}}{\left(1-{\tfrac {S_{1}S_{2}}{R_{1}R_{2}}}\right)\left(1+{\tfrac {R_{4}}{S_{4}}}\right)}}}}}
Kinetic Ratios: Torque Conversion
Torque Ratio[ c] R & 1
μ
R
=
(
1
−
R
1
R
2
S
1
S
2
η
0
2
)
(
1
+
S
3
R
3
η
0
)
(
1
+
S
4
R
4
η
0
)
{\displaystyle \mu _{R}=\left(1-{\tfrac {R_{1}R_{2}}{S_{1}S_{2}}}{\eta _{0}}^{2}\right)\left(1+{\tfrac {S_{3}}{R_{3}}}\eta _{0}\right)\left(1+{\tfrac {S_{4}}{R_{4}}}\eta _{0}\right)}
μ
1
=
(
1
+
R
2
S
2
η
0
)
(
1
+
S
3
R
3
η
0
)
(
1
+
S
4
R
4
η
0
)
{\displaystyle \mu _{1}=\left(1+{\tfrac {R_{2}}{S_{2}}}\eta _{0}\right)\left(1+{\tfrac {S_{3}}{R_{3}}}\eta _{0}\right)\left(1+{\tfrac {S_{4}}{R_{4}}}\eta _{0}\right)}
Torque Ratio[ c] 2 & 3
μ
2
=
(
1
+
S
1
R
1
η
0
)
(
1
+
S
3
R
3
η
0
)
(
1
+
S
4
R
4
η
0
)
{\displaystyle \mu _{2}=\left(1+{\tfrac {S_{1}}{R_{1}}}\eta _{0}\right)\left(1+{\tfrac {S_{3}}{R_{3}}}\eta _{0}\right)\left(1+{\tfrac {S_{4}}{R_{4}}}\eta _{0}\right)}
μ
3
=
(
1
+
S
3
R
3
η
0
)
(
1
+
S
4
R
4
η
0
)
{\displaystyle \mu _{3}=\left(1+{\tfrac {S_{3}}{R_{3}}}\eta _{0}\right)\left(1+{\tfrac {S_{4}}{R_{4}}}\eta _{0}\right)}
Torque Ratio[ c] 5–7
μ
5
=
1
1
{\displaystyle \mu _{5}={\tfrac {1}{1}}}
μ
6
=
1
1
+
R
3
S
3
⋅
1
η
0
(
1
+
R
1
S
1
η
0
)
(
1
+
R
4
S
4
η
0
)
{\displaystyle \mu _{6}={\tfrac {1}{1+{\tfrac {{\tfrac {R_{3}}{S_{3}}}\cdot {\tfrac {1}{\eta _{0}}}}{\left(1+{\tfrac {R_{1}}{S_{1}}}\eta _{0}\right)\left(1+{\tfrac {R_{4}}{S_{4}}}\eta _{0}\right)}}}}}
μ
7
=
1
1
+
R
3
S
3
⋅
1
η
0
(
1
+
S
2
R
2
η
0
)
(
1
+
R
4
S
4
η
0
)
{\displaystyle \mu _{7}={\tfrac {1}{1+{\tfrac {{\tfrac {R_{3}}{S_{3}}}\cdot {\tfrac {1}{\eta _{0}}}}{\left(1+{\tfrac {S_{2}}{R_{2}}}\eta _{0}\right)\left(1+{\tfrac {R_{4}}{S_{4}}}\eta _{0}\right)}}}}}
Torque Ratio[ c] 4 & 8 & 9
μ
4
=
1
+
S
4
R
4
η
0
{\displaystyle \mu _{4}=1+{\tfrac {S_{4}}{R_{4}}}\eta _{0}}
μ
8
=
1
1
+
R
3
S
3
⋅
1
η
0
1
+
R
4
S
4
η
0
{\displaystyle \mu _{8}={\tfrac {1}{1+{\tfrac {{\tfrac {R_{3}}{S_{3}}}\cdot {\tfrac {1}{\eta _{0}}}}{1+{\tfrac {R_{4}}{S_{4}}}\eta _{0}}}}}}
μ
9
=
1
1
+
R
3
S
3
⋅
1
η
0
(
1
−
S
1
S
2
R
1
R
2
⋅
1
η
0
2
)
(
1
+
R
4
S
4
η
0
)
{\displaystyle \mu _{9}={\tfrac {1}{1+{\tfrac {{\tfrac {R_{3}}{S_{3}}}\cdot {\tfrac {1}{\eta _{0}}}}{\left(1-{\tfrac {S_{1}S_{2}}{R_{1}R_{2}}}\cdot {\tfrac {1}{{\eta _{0}}^{2}}}\right)\left(1+{\tfrac {R_{4}}{S_{4}}}\eta _{0}\right)}}}}}
^ Revised 14 January 2026Nomenclature
S
n
=
{\displaystyle S_{n}=}
sun gear: number of teeth
R
n
=
{\displaystyle R_{n}=}
ring gear: number of teeth
C
n
=
{\displaystyle \color {gray}{C_{n}=}}
carrier or planetary gear carrier (not needed)
s
n
=
{\displaystyle s_{n}=}
sun gear: shaft speed
r
n
=
{\displaystyle r_{n}=}
ring gear: shaft speed
c
n
=
{\displaystyle c_{n}=}
carrier or planetary gear carrier: shaft speed
With
n
=
{\displaystyle n=}
gear is
i
n
=
{\displaystyle i_{n}=}
gear ratio or transmission ratio
ω
1
;
n
=
ω
t
=
{\displaystyle \omega _{1;n}=\omega _{t}=}
shaft speed shaft 1: input (turbine) shaft
ω
2
;
n
=
{\displaystyle \omega _{2;n}=}
shaft speed shaft 2: output shaft
T
1
;
n
=
T
t
=
{\displaystyle T_{1;n}=T_{t}=}
torque shaft 1: input (turbine) shaft
T
2
;
n
=
{\displaystyle T_{2;n}=}
torque shaft 2: output shaft
μ
n
=
{\displaystyle \mu _{n}=}
torque ratio or torque conversion ratio
η
n
=
{\displaystyle \eta _{n}=}
efficiency
i
0
=
{\displaystyle i_{0}=}
stationary gear ratio
η
0
=
{\displaystyle \eta _{0}=}
(assumed) stationary gear efficiency
^ a b c d e f g h i j k l m n o p q Gear Ratio (Transmission Ratio)
i
n
{\displaystyle i_{n}}
— Speed Conversion —
The gear ratio
i
n
{\displaystyle i_{n}}
is the ratio of
input shaft speed
ω
1
;
n
{\displaystyle \omega _{1;n}}
to output shaft speed
ω
2
;
n
{\displaystyle \omega _{2;n}}
and therefore corresponds to the reciprocal of the shaft speeds
i
n
=
1
ω
2
;
n
ω
1
;
n
=
ω
1
;
n
ω
2
;
n
=
ω
t
ω
2
;
n
{\displaystyle i_{n}={\frac {1}{\frac {\omega _{2;n}}{\omega _{1;n}}}}={\frac {\omega _{1;n}}{\omega _{2;n}}}={\frac {\omega _{t}}{\omega _{2;n}}}}
^ a b c d e f g h i j k l m n o p q Torque Ratio (Torque Conversion Ratio)
μ
n
{\displaystyle \mu _{n}}
— Torque Conversion —
The torque ratio
μ
n
{\displaystyle \mu _{n}}
is the ratio of
output torque
T
2
;
n
{\displaystyle T_{2;n}}
to input torque
T
1
;
n
{\displaystyle T_{1;n}}
minus efficiency losses
and therefore corresponds (apart from the efficiency losses) to the reciprocal of the shaft speeds too
μ
n
=
i
n
η
n
;
η
0
=
ω
1
;
n
η
n
;
η
0
ω
2
;
n
=
T
2
;
n
η
n
;
η
0
T
1
;
n
{\displaystyle \mu _{n}=i_{n}\eta _{n;\eta _{0}}={\frac {\omega _{1;n}\eta _{n;\eta _{0}}}{\omega _{2;n}}}={\frac {T_{2;n}\eta _{n;\eta _{0}}}{T_{1;n}}}}
whereby
η
n
;
η
0
{\displaystyle \eta _{n;\eta _{0}}}
may vary from gear to gear according to the formulas listed in this table and
0
≤
η
n
;
η
0
≤
1
{\displaystyle 0\leq \eta _{n;\eta _{0}}\leq 1}
^ a b c d e f g h i j k l m Efficiency
The efficiency
η
n
{\displaystyle \eta _{n}}
is calculated
from the torque ratio
in relation to the gear ratio (transmission ratio)
η
n
=
μ
n
i
n
{\displaystyle \eta _{n}={\frac {\mu _{n}}{i_{n}}}}
Power loss for single meshing gears
is in the range of 1 % to 1.5 %
helical gear pairs, which are used to reduce noise in passenger cars, are in the upper part of the loss range
spur gear pairs, which are limited to commercial vehicles due to their poorer noise comfort, are in the lower part of the loss range
Corridor for torque ratio and efficiency
in planetary gearsets, the stationary gear ratio
i
0
{\displaystyle i_{0}}
is formed via the planetary gears and thus by two meshes
for reasons of simplification, the efficiency for both meshes together is commonly specified there
the efficiencies
η
0
{\displaystyle \eta _{0}}
specified here are based on assumed efficiencies for the stationary ratio
i
0
{\displaystyle i_{0}}
of
η
0
=
0.9800
{\displaystyle \eta _{0}=0.9800}
(upper value)
and
η
0
=
0.9700
{\displaystyle \eta _{0}=0.9700}
(lower value)
for both interventions together
The corresponding efficiency
for single-meshing gear pairs is
η
0
1
2
{\displaystyle {\eta _{0}}^{\tfrac {1}{2}}}
at
0.9800
1
2
=
0.98995
{\displaystyle 0.9800^{\tfrac {1}{2}}=0.98995}
(upper value)
and
0.9700
1
2
=
0.98489
{\displaystyle 0.9700^{\tfrac {1}{2}}=0.98489}
(lower value)
^ Layout
Input and output are on the same side
Planetary gearset 4 is on the input (turbine) side
Input shafts are, if actuated, S1 , R1 + S3 , and C3 + R4
Output shaft is C4
^ Total Ratio Span (Total Gear/Transmission Ratio) Nominal
ω
2
;
n
ω
2
;
1
=
ω
2
;
n
ω
2
;
1
ω
2
;
n
ω
2
;
1
ω
2
;
1
ω
2
;
n
=
1
ω
2
;
1
1
ω
2
;
n
=
ω
t
ω
2
;
1
ω
t
ω
2
;
n
=
i
1
i
n
{\displaystyle {\frac {\omega _{2;n}}{\omega _{2;1}}}={\frac {\frac {\omega _{2;n}}{\omega _{2;1}\omega _{2;n}}}{\frac {\omega _{2;1}}{\omega _{2;1}\omega _{2;n}}}}={\frac {\frac {1}{\omega _{2;1}}}{\frac {1}{\omega _{2;n}}}}={\frac {\frac {\omega _{t}}{\omega _{2;1}}}{\frac {\omega _{t}}{\omega _{2;n}}}}={\frac {i_{1}}{i_{n}}}}
A wider span enables the
downspeeding when driving outside the city limits
increase the climbing ability
when driving over mountain passes or off-road
or when towing a trailer
^ a b c Total Ratio Span (Total Gear Ratio/Total Transmission Ratio) Effective
ω
2
;
n
m
a
x
(
ω
2
;
1
;
|
ω
2
;
R
|
)
=
m
i
n
(
i
1
;
|
i
R
|
)
i
n
{\displaystyle {\frac {\omega _{2;n}}{max(\omega _{2;1};|\omega _{2;R}|)}}={\frac {min(i_{1};|i_{R}|)}{i_{n}}}}
The span is only effective to the extent that
the reverse gear ratio
matches that of 1st gear
see also Standard R:1
Digression Reverse gear
is usually longer than 1st gear
the effective span is therefore of central importance for describing the suitability of a transmission
because in these cases, the nominal spread conveys a misleading picture
which is only unproblematic for vehicles with high specific power
Market participants
Manufacturers naturally have no interest in specifying the effective span
Users have not yet formulated the practical benefits that the effective span has for them
The effective span has not yet played a role in research and teaching
Contrary to its significance
the effective span has therefore not yet been able to establish itself
either in theory
or in practice.
End of digression
^ Ratio Span's Center
(
i
1
i
n
)
1
2
{\displaystyle (i_{1}i_{n})^{\frac {1}{2}}}
The center indicates the speed level of the transmission
Together with the final drive ratio
it gives the shaft speed level of the vehicle
^ Average Gear Step
(
ω
2
;
n
ω
2
;
1
)
1
n
−
1
=
(
i
1
i
n
)
1
n
−
1
{\displaystyle \left({\frac {\omega _{2;n}}{\omega _{2;1}}}\right)^{\frac {1}{n-1}}=\left({\frac {i_{1}}{i_{n}}}\right)^{\frac {1}{n-1}}}
There are
n
−
1
{\displaystyle n-1}
gear steps between
n
{\displaystyle n}
gears
with decreasing step width
the gears connect better to each other
shifting comfort increases
^ Sun 4: sun gear of gearset 4
^ Ring 4: ring gear of gearset 4
^ Sun 3: sun gear of gearset 3
^ Ring 3: ring gear of gearset 3
^ Sun 2: sun gear of gearset 2
^ Ring 2: ring gear of gearset 2
^ Sun 1: sun gear of gearset 1
^ Ring 1: ring gear of gearset 1
^ a b c Standard 50:50 — 50 % Is Above And 50 % Is Below The Average Gear Step —
With steadily decreasing gear steps (yellow highlighted line Step )
and a particularly large step from 1st to 2nd gear
the lower half of the gear steps (between the small gears; rounded down, here the first 4) is always larger
and the upper half of the gear steps (between the large gears; rounded up, here the last 4) is always smaller
than the average gear step (cell highlighted yellow two rows above on the far right)
lower half: smaller gear steps are a waste of possible ratios (red bold)
upper half: larger gear steps are unsatisfactory (red bold)
^ a b c d Standard R:1 — Reverse And 1st Gear Have The Same Ratio —
The ideal reverse gear has the same transmission ratio as 1st gear
no impairment when maneuvering
especially when towing a trailer
a torque converter can only partially compensate for this deficiency
Plus 11.11 % minus 10 % compared to 1st gear is good
Plus 25 % minus 20 % is acceptable (red)
Above this is unsatisfactory (bold)
see also Total Ratio Span (Total Gear/Transmission Ratio) Effective
^ Standard 1:2 — Gear Step 1st To 2nd Gear As Small As Possible —
With continuously decreasing gear steps (yellow marked line Step )
the largest gear step is the one from 1st to 2nd gear, which
for a good speed connection and
a smooth gear shift
must be as small as possible
A gear ratio of up to 1.6667 : 1 (5 : 3) is good
Up to 1.7500 : 1 (7 : 4) is acceptable (red)
Above is unsatisfactory (bold)
^ a b From large to small gears (from right to left)
^ a b c d e f g Standard STEP — From Large To Small Gears: Steady And Progressive Increase In Gear Steps —
Gear steps should
increase: Δ Step (first green highlighted line Δ Step ) is always greater than 1
As progressive as possible: Δ Step is always greater than the previous step
Not progressively increasing is acceptable (red)
Not increasing is unsatisfactory (bold)
^ a b c d e Standard SPEED — From Small To Large Gears: Steady Increase In Shaft Speed Difference —
Shaft speed differences should
increase: Δ Shaft Speed (second line marked in green Δ (Shaft) Speed ) is always greater than the previous one
1 difference smaller than the previous one is acceptable (red)
2 consecutive ones are a waste of possible ratios (bold)
^ 280 N⋅m (207 lb⋅ft ) for both gasoline and diesel[ 1]
^ 450 N⋅m (332 lb⋅ft ) for gasoline[ 1]
^ 480 N⋅m (354 lb⋅ft ) for diesel[ 1]
^ 91/133 or 104/152
^ Thereof 1 dog break[ 3]
^ Thereof 1 dog clutch[ 3]
^ Permanently coupled elements
C1 , C2 , and R3
S3 and S4
C3 and R4
^ Dog brake blocks S3 and S4
^ Blocks S1
^ Blocks R2
^ Couples S1 with input (turbine)
^ Couples C3 and R4 with input (turbine)
^ Dog clutch couples R1 and S2 with input (turbine)
^ a b c d Ordinary Noted
For direct determination of the gear ratio
^ a b c d Elementary Noted
Alternative representation for determining the transmission ratio
Contains only operands
With ordinary fractions of both central gears of a planetary gearset
Or with the value 1
As a basis
For reliable
And traceable
Determination of the torque conversion rate and efficiency
How It Works
An Animated Drive Line Schematic & A Rotational Speeds Nomogram
These ordinates are positioned on the abscissa in strict accordance with the proportions of the sun gears' teeth numbers relative to those of their rings. Consequently, the output ratios on the ordinate C4 (carrier of planetary gearset 4) follows closely to those of the actual transmission. Note that elements A and F are labelled swapped (cf. legend below).
Nomogram
▶️ Interactive Nomogram Archived 2017-02-02 at the Wayback Machine
This interactive nomogram is a real geometric calculator exactly representing the rotational speeds of the transmission's 3x4 = 12 internal shafts for each of its 9 ratios (+ reverse ), grouped according to their 5 permanent coupling on 4 joint ordinates and 3 independent ordinates. These ordinates are positioned on the abscissa in strict accordance with the proportions of the sun gears' teeth numbers relative to those of their rings. Consequently, the output ratios on the 6th ordinate (carrier of the fourth planetary gearset ) follows closely those of the actual transmission. This advantageous geometric construction sets us free from Robert Willis ' famous and tedious formula,[ 4] because all calculations are exclusively determined by lengths ratios, respectively teeth numbers on the abscissa for the 4 epicyclic ratios, and of rotational speeds on the 6th ordinate for the 10 gear ratios.
Legend
A : Dog brake (blocks S3 and S4 )
C : Brake (blocks S1 )
D : Brake (blocks R2 )
B : Clutch (couples S1 with input shaft)
E : Clutch (couples C3 and R4 with input shaft)
F : Dog clutch (couples R1 and S2 with input shaft)
Applications
Acura
TLX (2015–2020, V6 models)
MDX (2016–2020, non-hybrid models)
Alfa Romeo
Chrysler
Dodge
Hornet (2023–2025, 2.0L turbo engine)
FIAT
MG
Opel/Vauxhall
Honda
Infiniti
Jeep
Ram Trucks
Land Rover
Jaguar
Nissan
Technical imperfections
The transmission has been problematic, as customers of Jeep, Chrysler, and Acura models equipped with the transmission have experienced problems in their vehicles regarding slow shifting and noisy operation. ZF has said this is due to software problems, not mechanical issues.[ 8]
Chrysler issued Technical Service Bulletins (TSB) for the 2014 Jeep Cherokee to "fix rough and delayed gearshifts", and Acura has issued transmission-related recalls for the 2015 Acura TLX .[ 9] [ 10]
Production
Production of the 9HP started in 2013 at ZF's Gray Court facility in Laurens, South Carolina . 400,000 units are produced per year.[ 11]
Production of the 9HP for Fiat and Chrysler vehicles began in May 2013 at Indiana Transmission Plant I (ITPI), followed by Tipton Transmission Plant in Tipton County, Indiana in May 2014.[ 12]
See also
References